Mnementh on 21 February 2013
| Bajablo said: The fun thing about it is that they are using x86 instructions.. that is 32b machine standard. but they have 8gigs of memory.. so either they have to have a dynamic memory pointer of some sort or some custom instructions that allow them to use all of the memory. |
What? For a very long time now, the x86-architecture has different address-bit-length then data-bit-length. Going back to the 80286, it had 16 bits for data (range of 0-65535), but an address-range of 20 bits (=1 Megabyte). Also the x86-architecture has differing data-size over time. As you see, the 80286 has 16bit, the 80386 introduced 32bit and for some years now they support 64bit. I don't know much about the Jaguar-architecture itself, but as the AMD-extension for 64bit is now used commonly in the x86-architecture (even by Intel), I guess it is also included in the newer AMD-architecture.
