It's pretty heavy (Calc)
Leatherhat on July 6th, 2012 3pm. Vita sales:"3 mil for COD 2 mil for AC. Maybe more. " thehusbo on July 6th, 2012 5pm. Vita sales:"5 mil for COD 2.2 mil for AC."
It's pretty heavy (Calc)
Leatherhat on July 6th, 2012 3pm. Vita sales:"3 mil for COD 2 mil for AC. Maybe more. " thehusbo on July 6th, 2012 5pm. Vita sales:"5 mil for COD 2.2 mil for AC."
I'm sure my Algebra 2 mind can handle it.
Post it in the thread.
Kimi wa ne tashika ni ano toki watashi no soba ni ita
Itsudatte itsudatte itsudatte
Sugu yoko de waratteita
Nakushitemo torimodosu kimi wo
I will never leave you
OK
Determne tthe following about the graph of the equation: y= 8/x^3 - 6/x
Is the graph symmetric with respect to: the x-axis, the y-axis, or the origin
Find all vertical/horizontal asymptotes
Find the x-coordinates of each point at which y has a relative maximum or minimum'
Find the x-coordinate of each point of inflection
Leatherhat on July 6th, 2012 3pm. Vita sales:"3 mil for COD 2 mil for AC. Maybe more. " thehusbo on July 6th, 2012 5pm. Vita sales:"5 mil for COD 2.2 mil for AC."
Well that's simple, you just take the conjugate of the inverse matrix and divide by e to the power of a square slice of pie.
Kimi wa ne tashika ni ano toki watashi no soba ni ita
Itsudatte itsudatte itsudatte
Sugu yoko de waratteita
Nakushitemo torimodosu kimi wo
I will never leave you
Ugh, I hate hitting the post button on accident
Anyway, let's see if I can help
dtewi said: Well that's simple, you just take the conjugate of the inverse matrix and divide by e to the power of a square slice of pie. |
Yes, but before that, you have to apply the Fundamental Theoretical Principle to analyse the trends in the data, thereby showing the asymptotic functions of the inverse.
SaviorX said: OK Determne tthe following about the graph of the equation: y= 8/x^3 - 6/x Is the graph symmetric with respect to: the x-axis, the y-axis, or the origin Find all vertical/horizontal asymptotes Find the x-coordinates of each point at which y has a relative maximum or minimum' Find the x-coordinate of each point of inflection |
Throw the equation in there (you have to remove the "y=")
http://www.coolmath.com/graphit/
That'll give you an idea of the answers, as for the rest...it's just applying the formulas. Find the first and second derivative of the equation, I don't remember the exact conditions of point of inflection, but I think it was Fx = 0 and Fxx = 0....I can't remember that exactly
http://library.wolfram.com/webMathematica/Education/WalkD.jsp
http://en.wikipedia.org/wiki/Second_derivative_test
With those two links you should be able to do most of it easy peasy.
Edit: Points of inflection can be found where f'' = 0
Asymptotes can be found by turning the equation into a whatdayacall it, when you have only a numerator and denominator, and then solve the top for zero which is your horizontal asymptotes and the bottom for zero which are your verticle asymptotes. By the looks of the graph they're about the origin though. At least I think that should work.
About Us |
Terms of Use |
Privacy Policy |
Advertise |
Staff |
Contact
Display As Desktop
Display As Mobile
© 2006-2024 VGChartz Ltd. All rights reserved.