Here's the answer:

(1+1+1)! = 6

2+2+2 = 6

(3*3)-3 = 6

√4+√4+√4 = 6

(5/5)+5 = 6

6*6/6 = 6

7-(7/7) = 6

³√8+³√8+³√8 = 6

(9/√9)+√9 = 6

There are some other accepted answers too.

i do not accept 8, as a cubed root involves the use of the "3".


the riddle has flaws!

You highly convoluted answer for the number four included squares, or the number two!

I am drowning in the hypocrisy.

Yeah...when no number are mentioned above a root, it means it's 2.

²√4+²√4+²√4 = 6

I argue the riddle i still flawed. You are aware that square root is also (1/2), right? that's technically adding numbers!

^^really, so square root of 9 is 4.5

You're ruining the thread with your mathematical paradoxes!

So, here's an intelligent one.

Are you good at maths? Complete the last two in this sequence:

1=3, 2=3, 3=5, 4=4, 5=4, 6=3, 7=5, 8=5, 9=4, 10=3, 11=?, 12=?

Since nobody is willing to try an answer I'll go ahead and probably ridicule myself with this answer:

11=3, 12=5

11 =eleven = 6 letters
12 = twelve = 6 letters

?

^^ that makes much more sense!