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Forums - General Discussion - Does 0.999... Equal 1?

steven787 on 24 September 2008
skeezer said:
1/3 = .333333......

1/3 X 3 = 1

.33333.....X 3 = .9999.............


So Maybe...I made a thread about this before...I'll go look for it

 

But 1/3 does not equal .33333.... it equals .3-bar

1/3 ~=~ .333333

 

The question arises from our use of the decimal counting system, if we used a base-3 system it would be more accurate for dividing by 3.  Of course than nothing else would work.

In that system then 1/3 = .1; but we don't use a base-3 system.

 



I would cite regulation, but I know you will simply ignore it.

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Kane on 24 September 2008
dtewi said:
Kane said:
No, the one is a number that consists out of four numbers and the other consists just out of one

My god. You clearly need to retake 3rd Grade Arithmetic.

The "..." in mathematics is used to denote that a number goes on forever.

 


you use wiki as a source?

dtewi on 24 September 2008

Yes, 0.999999999............... does equal 1.

Let's use a simple algebraeic equation.

Let c = 0.999...

10c= 9.9999.....

10c -c = 9

9c/9 = 1.

c = c

1 = 0.999...



Kimi wa ne tashika ni ano toki watashi no soba ni ita

Itsudatte itsudatte itsudatte

Sugu yoko de waratteita

Nakushitemo torimodosu kimi wo

I will never leave you

skeezer on 24 September 2008
steven787 said:
skeezer said:
1/3 = .333333......

1/3 X 3 = 1

.33333.....X 3 = .9999.............


So Maybe...I made a thread about this before...I'll go look for it

 

But 1/3 does not equal .33333.... it equals .3-bar

1/3 ~=~ .333333

 

The question arises from our use of the decimal counting system, if we used a base-3 system it would be more accurate for dividing by 3.  Of course than nothing else would work.

In that system then 1/3 = .1; but we don't use a base-3 system.

 

The "......." is suppose to signify a -bar.

 



^_^

Kane on 24 September 2008

Let c = 2

10c= 2

10c -c = 8

8c/8 = 1.

c = c

1 = 2

hahaha WHAT?



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twilit on 24 September 2008
dtewi said:
Yes, 0.999999999............... does equal 1.

Let's use a simple algebraeic equation.

Let c = 0.999...

10c= 9.9999.....

10c -c = 9

9c/9 = 1.

c = c

1 = 0.999...

If you knew the answer what was the point of this thread...

 



theprof00 on 24 September 2008

is dtwei always like this?



dtewi on 24 September 2008
Kane said:
dtewi said:
Kane said:
No, the one is a number that consists out of four numbers and the other consists just out of one

My god. You clearly need to retake 3rd Grade Arithmetic.

The "..." in mathematics is used to denote that a number goes on forever.

 

 

you use wiki as a source?

No! Every single person who was taken elementary math knows that the "..." means infinty, goes on forever, ad infinitum. Forever! FOREVER!

It is common knowledge for god's sake!



Kimi wa ne tashika ni ano toki watashi no soba ni ita

Itsudatte itsudatte itsudatte

Sugu yoko de waratteita

Nakushitemo torimodosu kimi wo

I will never leave you

Kane on 24 September 2008
theprof00 said:
is dtwei always like this?

and he never admits he is WRONG

steven787 on 24 September 2008
skeezer said:
steven787 said:
skeezer said:
1/3 = .333333......

1/3 X 3 = 1

.33333.....X 3 = .9999.............


So Maybe...I made a thread about this before...I'll go look for it

 

But 1/3 does not equal .33333.... it equals .3-bar

1/3 ~=~ .333333

 

The question arises from our use of the decimal counting system, if we used a base-3 system it would be more accurate for dividing by 3.  Of course than nothing else would work.

In that system then 1/3 = .1; but we don't use a base-3 system.

 

The "......." is suppose to signify a -bar.

 

 

Than the bolded part is wrong.

If "......" is bar, then .33333...... * 3 =1 and not .99999......

 



I would cite regulation, but I know you will simply ignore it.