SuperMarioWorld said:
Zkuq said:
SuperMarioWorld said:
Zkuq said:
SuperMarioWorld said:
the step 'subtract x' is a trick. you are treating x as a constant not a variable. so when you say subtract x it means subtract 0.99999 therefore your proof doesn't really hold up mathematically. its a trick
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x = 0.999... and therefore 'subtract x' is the same thing as 'subtract 0.999...'. You can operate on both sides of an equation; the form you operate on each side is up to you to decide as long as both forms are equal. Besides, your point about treating x as a constant instead of a variable doesn't make much sense. x is x and it has a known value; what's the problem?
Oh I get it. You're just trying to mess with us.
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i'm not messing with you. the problem with his proof is he is treating x as a variable. but it is a constant as he has stated in the first step. you can't just suddenly decide x is a variable in the middle of a proof when he has stated it's a constant at the start of a proof. In a proof you must define x to a degree for example x is any positive integer. he defined x as 0.99999. nothing else. his proof is completely wrong.
http://en.wikipedia.org/wiki/User:ConMan/Proof_that_0.999..._does_not_equal_1
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If you think the proof is wrong, please do point out the step that's wrong and why. All you have is an ambiguous statement about what's wrong but if there's something wrong, you should point it out exactly because it's not obvious. What does a variable even mean to you? And what about the other proofs? Also, have you studied mathematics? Besides high school level, that is.
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I did point out the wrong step in my first post mate.
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No you didn't. As far as I'm concerned, all you did point out was your lack of basic understanding of manipulating equations. That, or my English is rusty. What do you even mean when you say he's treating it as a constant instead of a variable? Then let's assume that's a mistake: What does it affect and where?
