Jay520 said:
a + ar + ar^2 + ar^3 + ar^4 ... repeating IS equal to a/(1-r) That is the formula. Now for a, input 9/10. And for r, input (1/10). This equals 9/10 + 9/10(1/10)^1 + 9/10(1/10)^2 + 9/10(1/10)^3 ....which equals .9 + .09 + .009 which equals 0.9999999 So 0.9999999 = 9/10 + 9/10(1/10) + 9/10(1/10)^2 + 9/10(1/10)^2 which equals, according to the official formula, 9/10 / [1-(1/10)] which is 1. |
No, from my class, pretty much every time with these series it meant that these series APPROACHED these numbers. However they never actually reached them. In calculus you simplified them to such. The formula is simply one that is used to handle more complex geometric series, such as ones that may approach a number like .253 or something.
However, since the sum goes on infinitely, it does not ever actually equal to the number itself.








