| trasharmdsister12 said: To answer the question in the title I first went to look up the tech specs. Here's what I learned. Nintendo Wii (long-side flat):
Nintendo 3DS
To determine which is strongest I dropped them both from a height of 2 m. The acceleration due to gravity is 9.8 m/s^2. Using basic kinematics we know F=m*a. F(Wii) = 1.2 kg * 9.8 m/s^2 = 11.76 N (N = kg*m/s^2) F(3DS) = 0.235 kg * 9.8 m/s^2 = 2.303 N To take the size of these devices into account we divide the experienced force by the volume of the devices to see how much force is experienced per unit of the consoles size. Of course we're assuming uniform body structures for simple discussions sake. N(Wii) = F(Wii) / 1655.715 cm^3 = 0.0071 N/cm^3 N(3DS) = F(3DS) / 208.236 cm^3 = 0.0111 N /cm^3 It's shown that the 3DS sustains a larger force per unit volume, making it weaker. Furthermore, we have to remember that the 3DS is not a rigid body like the Wii due to the opening screen which reduces structural integrity even more. Therefore I scientifically conclude that the Wii is stronger than the 3DS. |
Not bad!
EDIT: Actually, 'strong' doesn't imply how much force it experiences (per unit volume as you've done). What you need to do is measure the tensile strength, i.e. how at what force the material breaks. Then you can use your data above and make a conclusion. Btw, where'd you learn physics?
