How long does it take to beat this game?

[Michael-5]

Griffin said:

Michael-5 said:

I just don't know what to say to you. Pretty major accusations your making. Have you even beated the game yourself? Remember I'm not talking about 100% completion, just getting a medal in each event and progressing. I also included Special Cups, as there are only what 8 of them? 100% completion would probably take closer to 100 hours, but that I have not done, and have no interest in doing.

Game took me 40 hours to beat myself, I found the number of races and general difficulty have dropped since the PS2 installments. Maybe I'm just getting better, but there are less cups in GT5.

But they still included the damn Vitz cup.....

I guess if we determine beating games based off your views, then i loaded up Halo Reach, that took 1min so it took me 1min to beat that game.

Wow, okay I'm just going to stop talking to you. To beat a FPS, would be to play the game, all the levels and see an ending. For GT5, I beat all the events, and got to the ending. Is there a difference? No. Just because I don't include B-Spec, which is not actually a new part of the game, doesn't mean anything. Do you have to unlock all the ending in a RPG to beat it? No. Do you have to beat a game on every difficulty setting? No.I got to the end cinematics in GT5, and I beat all the specials. It was beaten in 40 hours.

I mean, if I beat Halo single player, I still beat it. I don't have to do it again in co-op to claim that. Nor do I have to play a match of Firefight on every level.

I only counted Forza 3 as the time it took to beat Season Play, not the time to beat all the races. Why call me on GT, but not Forza? Beating all the races in Forza would be 100% completion, just like Beating B and A spec in GT5. Older GT games were significantly longer, and I gave them appropriate times. I only claimed the average was 40 hours for GT5, so get over youself. Stop insulting honest gamers just because the game you love is shorter then you wanted it to be.

Get over yourself.