Quick math help?

SHMUPGurus

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SHMUPGurus on 28 September 2009

Sorry... I'm doing linear algebra at the moment. This simple stuff is fun compared to that! @_@

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zexen_lowe on 28 September 2009

Scratch that, I'm sure it was free when I used it....5 years ago. I'll find you a new one

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c03n3nj0 on 28 September 2009

I though I learned that in Algebra 1....

Problem already solved, though.

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Boutros

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Boutros on 28 September 2009

SHMUPGurus said:
Sorry... I'm doing linear algebra at the moment. This simple stuff is fun compared to that! @_@

Whoo! I'm also doing linear algebra. And we both live in Québec! And we both speak french! We might even be in the same class O.o :P

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zexen_lowe on 28 September 2009

OK, Soriku, this one should do, try it

http://www.mathgv.com/

SHMUPGurus

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SHMUPGurus on 29 September 2009

Boutros said:

SHMUPGurus said:
Sorry... I'm doing linear algebra at the moment. This simple stuff is fun compared to that! @_@

Whoo! I'm also doing linear algebra. And we both live in Québec! And we both speak french! We might even be in the same class O.o :P

Oh, the excitement! Je viens de l'Estrie... Ça te dit de quoi? xD

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Watch my insane gameplay videos on my YouTube page!

zexen_lowe

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zexen_lowe on 29 September 2009

Soriku said:
Hmm, that program looks really complicated :P Are you sure it does things like parallel lines and perpendicular lines?

Ehm, it does more than that...I mean, the Windows Calculator does sine and cosine, that doesn't mean it can't do sums and multiplications

I never used that program, to be honest, I used Graphmatica (which I swear I have a free version), you can plot either by equation or by two points, so I guess this one should too

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zexen_lowe on 29 September 2009

Soriku said:
WTF this program makes no sense.

I'm trying to plot y = 5x + 3 but I have to input this in some function calculator or something?

Graph -> New Function -> Type it without the Y, just as 5x+3, and it's graphed. I'm trying to figure out if it graphs based on coordinates too

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Xxain on 29 September 2009

Rise over Run. Y=rise X= run

zexen_lowe

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zexen_lowe on 29 September 2009

Soriku said:

OK so I start out at 3. How many places do I go up and left? There's no points, only a line...

Plus do you know how to graph parallel/perpendicular lines?

Perpendicular functions have a slope (the number that's multiplying the x) that multiplied by the other fuction's slope is equal to -1

Therefore, the perpendicular equation would be y=-1x/5 + b, with b depending on which point you want it to pass

Paralell lines have the same slope, but different independent term, again, it depends for which point it should pass

I don't know what's your trouble, find the equation you need and graph it. Or you can't find the equation you need?

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