I'm working with limits (pretty basic, but still) right now, and I usually do pretty well with them having had Calc I before. However, this one problem has me stumped.

I have to find the limit as h approaches 0 of 8/x^2.

This is using the definition; take the limit as h approaches 0 of [f(x+h)-f(x)]/h

I can get it to the limit as h approaches 0 of [8/(2xh)+8/(h^2)]/h, but then I get stuck. I'm not even sure if this is right, actually, but I keep getting this far no matter how many ways I try to do it and then I can't get any farther. One thing I tried was to factor out a 1/h, and get rid of it that way, but I got 8/2x+8/h and then got stuck. 

Any help would be greatly appreciated!

EDIT: I found something that I did wrong with the fraction at the beginning. Hopefully I can figure this out, but I haven't gotten an answer yet...

EDIT 2: Okay, now I'm stuck on the limit as h approaches 0 of [8/(x^2+2xh+h^2)-8/x^2]/h.

* has been rendered Braindead*

Haha, sorry for the terrible notation, I dunno how to make it look any prettier though.

Sorry dude, you're about 10 years too late for me to remember how to do that crap.

right. its a simple derivative. You're just going through the proof part of it, but in Street Calculus, where you just do the short cut, the derivative is = -16X^(-3)

Well, if I use the shortcut then I don't get any credit. Otherwise I would just do that, since the question wants me to find the equation of the tangent line at a certain point. I can do that though.

I figured it out though, I was making a really stupid algebra mistake. And lol at that video.