By using this site, you agree to our Privacy Policy and our Terms of Use. Close
NolSinkler said:
DD_Bwest said:
NolSinkler said:
Metrium said:
As a Quebecer I want Quebec to leave Canada and become it's own country. So as you can guess, I'm totaly against this idea. We are not canadians so we are obviously farther from being americans.


That doesn't make sense.  If you're not Canadians, that makes you more likely to be an American, since Americans are also not Canadian.  Of course, I'd love it if Canadians could also be Americans...


 but if a canadian isnt a quebecer, wouldnt the canadian then be more likely to be american then?  Just because 2 things are not like a third thing, doesnt mean the first 2 are closer to that of eachother. 

What hes saying is Those in quebec who want independence  see themselves as their own identity, and dont want to be part of the others.  Quebec has a different culture then most of the rest of canada, and is very different then the yanks.

Not according to Set Theory.  Canadians are NOT American (definitionally), implying that the set of things Canadian are mutually exclusive to the set of things American.  Quebecers are NOT Canadian (given by first post here), meaning that they do not belong to the set of things Canadian, implying that they may still belong to the things American.

Simply:
Canadians = A
Americans = B
Quebecers = C

A intersect B = empty set
A intersect C = empty set
This is the given information.  Given this information we cannot conclude whether B intersect C is the empty set or not.

the thing is we are also given B intersect C = Empty set.    and as such, with no more information given, you cannot say that any of a/b  a/c  or b/c are closer then another.



I am Torgo, I take care of the place while the master is away.

"Hes the clown that makes the dark side fun.. Torgo!"

Ha.. i won my bet, but i wasnt around to gloat because im on a better forum!  See ya guys on Viz