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General - 0.9999.... = 1.0 - View Post

dsgrue3 said:

f(x,y) = x + 2

I can put an inifite number of y-values for any x to satisfy any output.

Either way x = 0.999... is not a function, as I've beaten to death already. 

I never said x = 0.9999 is a function. Not sure what the other things have to do with what I said either. Let me put it this way:

If x^2 = y^2, then we don't know if y = x. We just know y = x OR (-x). 

HOWEVER

if 10x = 10y, then we know x = y.
if 9x = 9y, then we know x = y.
if x/9 = y/9, then we know x = y.
Using these operations, we know 0.999... = 1

The above is always true. That's why the operations I used works, and the square operation would not have worked. And that's why I didn't use the square operation. So proving that the square operation brings back weird results does nothing to discount what I did, because I did multiplication and subtraction, which DO NOT give off weird results (unless 0 is used). 

Had I used the square operation, then you would have a point. But the operations I used are always fine for any number, which is what SuperMarioWorld tried (and failed) to disprove.

Again, 

Because the square function is not one-to-one, we cannot know if x=y even if x^2 = y^2.

However, if 10x = 10y or 9x = 9y or x/9 = y/9, then we do know x = y. This works all the time unless 0 is used.