| dsgrue3 said: I agree that in order to evaluate the function 1/(x^2) you need to limit it to a non-zero evaluation for x^2, however you are making a major error. What was given was this: x^2 = 4. The function is then f(x) = (x^2) - 4 not f(x) = (x^-2) - 4 (inverse function) so no limits need be imposed. Resolving f(x)=(x^2) - 4 is simply a quadratic at y intercept -4, which has x intercepts at 2 and -2 confirming them as solutions. |
I'm not sure where you're getting f(x) = x^2 - 4 from. The function should just be x^2. The output of the function is 4.
When you draw the inverse of a function, you have to restrict it to a one-to-one function before doing so. If the function is not one-to-one (which the quadratic function isn't), then it does not have an inverse.
