0.9999.... = 1.0

[dsgrue3]

Zkuq said:

I fail to see how you get 9.999... = 9 if you substitute there. Substitution brings the equation to this form:

    9(0.999...) = 9.999... - 0.999... = 9,

from which we get (divide by 9) 0.999... = 1. Right?

I see my error. I made 9 * 0.999... to 9.999... for some reason.