Calculus HELP? Please

[Vertigo-X]

dany612 said:

Vertigo-X said:

delta x is simply the small difference between one point along a curve and the next. As in ∆x = x2-x1

 

I suppose I could take a stab at it.

 

lim ∆x->0 [(x+∆x)^2-x^2]/∆x

lim ∆x->0 [(x^2+2x∆x-∆x^2)-x^2]/∆x

lim ∆x->0 [(x^2-x^2)+2x∆x-∆x^2]/∆x

lim ∆x->0 [2x-∆x]∆x/∆x

lim ∆x->0 2x-∆x = 2x

 

f(x) = x^2

lim ∆x->0 [f(x + ∆x) - f(x)]/∆x

AKA the derivative!

y = nx^m

dy/dx = (n*m)x^(m-1)

 

The derivative is the easy way to do it. :)

Okay you lost me in the bolded. So what would be the limit? 

The bolded part is extraneous and unnecessary. I was just showing off. ;)

 

The answer is above the bolded.