dany612 said:
thanks vertigo and chapset. Okay I have one question this time it involves rationalization, something which I understand more fully. Anyhow this question has this triangle shape as a coefficent which I assume is Delta but I don't recall it's revalance to this: find limit: ((x+∆x)^2-x^2)/∆x |
delta x is simply the small difference between one point along a curve and the next. As in ∆x = x2-x1
I suppose I could take a stab at it.
lim ∆x->0 [(x+∆x)^2-x^2]/∆x
lim ∆x->0 [(x^2+2x∆x-∆x^2)-x^2]/∆x
lim ∆x->0 [(x^2-x^2)+2x∆x-∆x^2]/∆x
lim ∆x->0 [2x-∆x]∆x/∆x
lim ∆x->0 2x-∆x = 2x
f(x) = x^2
lim ∆x->0 [f(x + ∆x) - f(x)]/∆x
AKA the derivative!
y = nx^m
dy/dx = (n*m)x^(m-1)
The derivative is the easy way to do it. :)
The BuShA owns all!