lim θ->0 (cos θ tan θ)/ θ = lim θ->0 [cos θ(sonθ/cosθ)]/θ = lim θ->0 (sin θ)/ θ = using the hospital rule ( which mean you use a derivative on top and in the bottom) lim θ->0 (cos θ)/1= 1/1 = 1
θ is just an other variable here
for the second one I am not 100% sure for this one
I used those two trigo identity: 1+ tg^2(x)= sec^2(x)
sec(x)= 1/cos(x) so sec^2(x)= 1^2/cos^2(x)= 1/cos^2(x)
lim x->0 tan^2(x)/x = lim x->0 (sec^2(x)-1)/x
lim x->0 [sec^2(x)]/x - 1/x = lim x->0 [1/cos^2(x)]/x - 1/x = lim x->0 1/xcos^2(x) - 1/x using the hospital rule you get lim x->0 0/something - 0/1 = 0
Bet reminder: I bet with Tboned51 that Splatoon won't reach the 1 million shipped mark by the end of 2015. I win if he loses and I lose if I lost.
