Rath said:
My statistics must be awful (last did it in high school), can somebody point out what I'm doing wrong? I figure there are 2^6 possible paths, all with equal probability and 7 paths where there are 5 or 6 right. 7/(2^6)=0.109. |
I stand corrected; you've probably done it more recently than I. I forgot about the variable of the irrelevant value's location, and erringly went with a 1/2^5 distribution, failing to account for the allowance of a slush spot. Sorry about that.
-dunno001
-On a quest for the truly perfect game; I don't think it exists...