| twesterm said: Fine, how about some simple statistic problems? |
Damn it I haven't had statistic classes yet, that's for next year's class. I'll try to figure out the answer though with reasoning rather than formulas because I do not know any of them.
Well, since the possibilities for the first question are 8:04, 8:05...8:10, there are 7 possibilities. then 7->100%. Since 8:04 represents one single possibility, then there is a probability of 14,29% for the train to arrive at 8:04.
For the second question, there are 3 possibilities, that it'll arrive at 8:08, 8:09 or 8:10. Then 3->100%. Since 8:08 represents one single possibility, then there is a probability of 33,33% for the train to arrive at 8:08.
For the last problem, since there's a failure rate of 10% for 20 consoles, then 2 of these consoles will fail. Since 8 have been already picked, that leaves us with 12 consoles, out of which 10 work and 2 fail. Now, 20->100% 2->10% of 20. And 12->60% of 20. 8->40% of 20.
Then we have 2->16,67% of 12. That's the chance we're looking for.
That's it I hope I'm right. Why don't you try solving my problem twesterm? from the looks of your problems you're really smart.
I encourage everyone to continue answering problems and posting further problems!







