| twesterm said: Now, if people are *really* in for some nerd stuff, here are some fun math problems (not high school level): Solution s3 / (s2 + 9)2 = (As + B) / (s2 + 9)2 + (Cs + D) / (s2 + 9) = (3): A[s / (s2 + 9)2] + B[1 / (s2 + 9)2] + C[ 1/ (s2 + 9)2] + (D / 3)(3 / (s2 + 9)) Using (1) and (2)... L-1[s3 / (s2 + 9)2] = A((1 / (2 * 3))t sin (3t)) + B( (1/(2 * 33)) sin (3t)) - ((1 / (2 * 32)) t cost (3t))) + C cost (3t) + (D / 3) sin (3t) multiply both sides of (3) by (s2 + 9)2 to get s3 = As + B + (s2 + 0)(Cs + D) S3: 1 = C, A = -9, (1): L-1[s / (ss + b2)] = (1 / 2b)t sin (bt) (2): L-1[1 / (s2 + b2)2] = )(1 / (2b3)) sin (bt)) - ((1 / 2b2) / (t cost (bt))) God I loved DiffEQ.
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You're right about my problem, good for you!
However I could never answer that now because that is beyond my current knowledge (though not perhaps capabilities). I don't even know who's Laplace...
Also, it seems that you guys have misunderstood me a little. Mathematic problems are not the same as mathematic exercises. Problems make you think, exercises make you practice knowledge. Please try to get some problems if you can.
By the way since you answered that one correctly, here's a harder one for anyone who may want to do it.
There's N which is equal to the product of the first 99 numbers. There's also M which is equal to the product of the reverse of the first 99 numbers. If a number has only one digit, its reverse is the same number. If the digit is of the form ab, its reverse is of the form ba. Calculate the value of
M/N
I shall wait for some answers!
