| TheLivingShadow said: Hey guys, I'm back and I'm going to say the solution to my prior problem. The guy who said the answer was 47 is right. The problem is really clear though, it's asking for the number of factors 2 P has, considering P=1x2x3x4x...x50. Now we know that there are 25 pair numbers in P, but, for example, 8 has 3 factors 2, because 8=2x2x2, 18 has 1 factor 2 because 18=3x3x2. Knowing that a multiplication means the addition of the powers, then we can get all factors 2 of the numbers 1, 2, 3, ..., 50 and add them. The result is 47. ;D Great job for the one who did it!
Since the addition of ABC was too easy, I'm gonna post the answer to this one, using only one-step solutions A=(528/84)==A= 44/7 *** *** Here's another problem I hope you like this one. Keep up with the problems guys! ;) An international organization has 32 members. ¿How many members would it have in 3 years if the number of members increases every year in respect to the last in a 50%? Answers: a)182 b)128 c)108 d)96 e)80 Picking an answer just for the hell of it won't do, you have to validate your answer! This problem is actually very easy. I'll be checking by tomorrow. Bye! |
Year 1: 32 * 1.5 = 48
Year 2: 48 * 1.5 = 72
Year 3: 72 * 1.5 = 108
Answer-- C
And the problem I asked ventures into Calculus II territory. I assume most high schools offer it since mine did (though it only ever had one student while I was there, not me) and I went to a fairly small podunk town public school.
Though if you even know what the second problem is asking, the first one doesn't involve any work (and I suppose Tyrranical is techinically right I believe, just wasn't the answer I was looking for). 
