marciosmg on 12 December 2008
(-2,4)
(2,4)
(1,1)
(-1,1)
(0,0)
A lot of points. Too easy.
y = ax2 + bx +c
(0,0) -> 0 = a02 + b0 +c --> c = 0
(1,1) -> 1 = a12 + b1 +0 --> a + b = 1 (A)
(-1,1) -> 1 = a(-1)2 + b(-1) + 0 --> a - b = 1 (B)
A + B = 2a = 2 --> a=1
A = a + b = 1 --> 1 +b = 1 --> b=0
Final equation --> y = x2