zexen_lowe on 12 December 2008
ctk495 said: y=mx.c Or atlest that's what I think. |
That's for lineal equations
marciosmg said: y = ax2 + bx +c xv = -b/2a yv = -(b2 - 4ac)/4a v = vertix (in your pics case xv = yv = 0) NOw, for every (x,y) you have, you throw it in the y = ... equation to find a, b and c Then you will get the whole y = ... eqaution which is the formula of that parabole (I don´t the name in english - that shape) |
That's right, but here's the easier form
a= (y-yv) / (x-xv)^2
b= - 2a * xv
c= yv + a * xv^2