largedarryl on 07 November 2008
| lightbleeder said: Don't know if this is right but I think it is, please correct if I'm wrong The derivative of x|sin(8x)| is sin(8x) + 8xcos(8x) for values higher than 0 and sin(-8x) - 8xcos(-8x) for values lower than 0. At zero is zero. |
It's been a long time since I did actual math work, but I don't think your answer comes up with the correct values where df/dx isn't defined. You definately need to come out with a df/dx that divides by a sinusodial function becuase the formula will result in a repeating undefined df/dx that occurs 16 times between 0 and 2pi.
So your derivative is definately wrong because there are no undefined df/dx values in your answer.
EDIT: Although I do realise that the 8x does have to come out of the equation, I missed it in my original numbers. I'm looking to correct my first answer because it is wrong, just wait for me to remember how to do math again.
