Okay I think I've got something :
We all know what happens if we have only two pirates (Scenario 1) :
4 - 100
5 - 0
It passes on the tie breaker
Now for 3 pirates (Scenario 2) :
3 - 100, 4 - 0, 5 - 0 would get 3 killed but if 3 is killed we go back to scenario 1 so at this time pirate 5 would accept anything over 0. So at 3 pirates the only possible outcome is :
3 - 99
4 - 0
5 - 1
This gets accept by 3 and 5.
Now if we have 4 pirates (scenario 3):
Pirate 2 knows pirate 5 gets 1 piece in scenario 2 and 0 in scenario 1 so he'll be willing to take the 1 piece again . So we get :
2 - 99
3 - 0
4 - 0
5 - 1
This gets accepted in the tie breaker.
Now we get to our actual scenario, 5 pirates :
Since pirate 4 gets nothing in scenarios 2 & 3, he'll be willing to take anything over 0. So we get this offer :
1 - 98
2 - 0
3 - 0
4 - 1
5 - 1
Final answer?
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