zexen_lowe said:
And 0 to any power is 0. The correct answer for 0^0 is indeterminate. There are some mathematical branches who use 0^0=1 to avoid complications and needing to create specific rules for it, but in general is treated as 0^0=Indeterminate
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No, it's only indeterminate as you're approaching it. At 0^0, it's precisely 1. People confuse it because it's considered indeterminate as a limit and you can use L'Hospital's rule with it. It's just like 1^Infinity. 1^Infinity is 1, but the limit as something approaches it is indeterminate.








