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ultima

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ultima on 22 August 2009

zexen_lowe said:

D_Boy said:

zexen_lowe said:

Does that mean the seventh root of 32, or 7 multiplying the square root of 32? If the former, it's irreductible, if the latter, it's
7 x 4 x √2, thus 28 x√2, what D_Boy said

Pretty sure it is the latter. I have never seen a question asking the 7th root of a number...when I was at school I mean.

Well, yeah, it would make no sense, since 7 is prime, but I just wanted to make sure

What does that have to do with anything???

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D_Boy on 22 August 2009

ultima said:

zexen_lowe said:

D_Boy said:

zexen_lowe said:

Does that mean the seventh root of 32, or 7 multiplying the square root of 32? If the former, it's irreductible, if the latter, it's
7 x 4 x √2, thus 28 x√2, what D_Boy said

Pretty sure it is the latter. I have never seen a question asking the 7th root of a number...when I was at school I mean.

Well, yeah, it would make no sense, since 7 is prime, but I just wanted to make sure

What does that have to do with anything???

Well...nothing. I think he thought that the 7 is in the square root. You can have a 7th root of a number though...like 7th sqrt(128) = 2

zexen_lowe

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zexen_lowe on 22 August 2009

ultima said:

zexen_lowe said:

D_Boy said:

zexen_lowe said:

Does that mean the seventh root of 32, or 7 multiplying the square root of 32? If the former, it's irreductible, if the latter, it's
7 x 4 x √2, thus 28 x√2, what D_Boy said

Pretty sure it is the latter. I have never seen a question asking the 7th root of a number...when I was at school I mean.

Well, yeah, it would make no sense, since 7 is prime, but I just wanted to make sure

What does that have to do with anything???

I don't understand what you mean. To be able to reduce a prime number-th root, the number inside (does it have a name?) needs to be factorizable into something that is elevated to a higher exponent. So, to reduce a 7th root, you gotta have something that is elevated to the seventh or more. Given how quickly numbers escalate, it seems to me like a waste.

On the other hand, if the number were not prime, it would make more sense, for example, you can reduce easily a 6th root with a squared or cubed number, like 6√27 (6th root, not 6 times) = √3, that would make a lot more sense

ultima

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ultima on 22 August 2009

zexen_lowe said:

ultima said:

zexen_lowe said:

D_Boy said:

zexen_lowe said:

Does that mean the seventh root of 32, or 7 multiplying the square root of 32? If the former, it's irreductible, if the latter, it's
7 x 4 x √2, thus 28 x√2, what D_Boy said

Pretty sure it is the latter. I have never seen a question asking the 7th root of a number...when I was at school I mean.

Well, yeah, it would make no sense, since 7 is prime, but I just wanted to make sure

What does that have to do with anything???

I don't understand what you mean. To be able to reduce a prime number-th root, the number inside (does it have a name?) needs to be factorizable into something that is elevated to a higher exponent. So, to reduce a 7th root, you gotta have something that is elevated to the seventh or more. Given how quickly numbers escalate, it seems to me like a waste.

On the other hand, if the number were not prime, it would make more sense, for example, you can reduce easily a 6th root with a squared or cubed number, like 6√27 (6th root, not 6 times) = √3, that would make a lot more sense

Oh, I see what you mean... nvm

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d21lewis on 22 August 2009

*must try not to look stupid*

"07734" looks like "hELLO" if you use a calculator and turn it upside down.

*heh, heh....they suspect nothing!*

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Gnac on 22 August 2009

d21lewis said:
*must try not to look stupid*

"07734" looks like "hELLO" if you use a calculator and turn it upside down.

*heh, heh....they suspect nothing!*

Try it with "5318008". I almost fell off my chair!

WHERE IS MY KORORINPA 3