tell me how to simplify 7√32
it still needs to be a square root i think
so will you guys help me?
tell me how to simplify 7√32
it still needs to be a square root i think
so will you guys help me?
http://www.worsleyschool.net/science/files/squareroot/page.html
Also: Nice thread title. Very descriptive.
WHERE IS MY KORORINPA 3
Also...at Gnac...that link is horrible. That doesn't help at all. Here is how it works in detail. √8=√(4x2)=√4 x √2. Now √4=2...therefore √8=2√2. Same as √32=√(4x8)=√(4x4x2)=√4 x √4 x √2=2x2x√2=4√2. So...7√32 = 7 x 4√2 = 28√2
Does that mean the seventh root of 32, or 7 multiplying the square root of 32? If the former, it's irreductible, if the latter, it's
7 x 4 x √2, thus 28 x√2, what D_Boy said

| D_Boy said: Also...at Gnac...that link is horrible. That doesn't help at all. Here is how it works in detail. √8=√(4x2)=√4 x √2. Now √4=2...therefore √8=2√2. Same as √32=√(4x8)=√(4x4x2)=√4 x √4 x √2=2x2x√2=4√2. So...7√32 = 7 x 4√2 = 28√2 |
I know. *beams*
WHERE IS MY KORORINPA 3
| zexen_lowe said: Does that mean the seventh root of 32, or 7 multiplying the square root of 32? If the former, it's irreductible, if the latter, it's |
Pretty sure it is the latter. I have never seen a question asking the 7th root of a number...when I was at school I mean.
7 (square root 16)(square root 2) = 7*4*(sqrt2) = 28 sqrt2
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D_Boy said:
Pretty sure it is the latter. I have never seen a question asking the 7th root of a number...when I was at school I mean. |
Well, yeah, it would make no sense, since 7 is prime, but I just wanted to make sure

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