(4!)/(square(4)+square(4)) = 6
(9+9)/(square(9)) = 6

The first one is impossible!
Kimi wa ne tashika ni ano toki watashi no soba ni ita
Itsudatte itsudatte itsudatte
Sugu yoko de waratteita
Nakushitemo torimodosu kimi wo
I will never leave you
Cube root of 8 + Cube root of 8 + Cube root of 8 = 6
Kimi wa ne tashika ni ano toki watashi no soba ni ita
Itsudatte itsudatte itsudatte
Sugu yoko de waratteita
Nakushitemo torimodosu kimi wo
I will never leave you
(7 squared) - 7 divided by 7 = 6
Kimi wa ne tashika ni ano toki watashi no soba ni ita
Itsudatte itsudatte itsudatte
Sugu yoko de waratteita
Nakushitemo torimodosu kimi wo
I will never leave you
5 divided by 5 plus 5 = 6
Kimi wa ne tashika ni ano toki watashi no soba ni ita
Itsudatte itsudatte itsudatte
Sugu yoko de waratteita
Nakushitemo torimodosu kimi wo
I will never leave you
The first one is annoying me. I've gotten five and seven.
Kimi wa ne tashika ni ano toki watashi no soba ni ita
Itsudatte itsudatte itsudatte
Sugu yoko de waratteita
Nakushitemo torimodosu kimi wo
I will never leave you
(log(2) of (1+1)^7) - 1 = 6
That's really the only thing I can think of.
Kimi wa ne tashika ni ano toki watashi no soba ni ita
Itsudatte itsudatte itsudatte
Sugu yoko de waratteita
Nakushitemo torimodosu kimi wo
I will never leave you


Assuming dtewi's answer is right let's move on:
What's the next number is this series?
1, 11, 21, 1211, 111221, 312211, 13112221, ?
Signature goes here!
| TruckOSaurus said: Assuming dtewi's answer is right let's move on: What's the next number is this series? 1, 11, 21, 1211, 111221, 312211, 13112221, ? |
The is one 1 in the first segment. 11. Two one's there. 21. One two and one one. 1211.
The last one has one 1, one three, two one's, three two's, and one one in that order.
1113213211.
Kimi wa ne tashika ni ano toki watashi no soba ni ita
Itsudatte itsudatte itsudatte
Sugu yoko de waratteita
Nakushitemo torimodosu kimi wo
I will never leave you
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