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Forums - General Discussion - Can you scientifically prove to me that 2+2= 4?

Eek! Teh maths!




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no its not 4! i worked it out, and i got 100000000000000000000000000000000000000000000000000000000000000



dtewi said:
That was just a simple trick I got off a random website.

2+2 is most certainly not equal to 5.

Do you want me to show you two others so you can prove it wrong?

 

They probably divide by zero, take the log of a negative number, or something like that.



No, they used Square Roots. As you should know, an equation usually has as many solutions as its highest degree.

For example, X^2 = 1 has two solutions, -1 and 1. Does this mean -1 and 1 are equal though?



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lets use imaginary numbers to resolve this problem

z= ai + b

 where:

i is the imaginary part

we can make b = 0, because 0 is a neutral number

i = √(-1)

i 2 = -1

i4 = 1

i4 + i4 = 2i4 = 2(1)*  = 2

i4 + i4 + i4 + i4 = (i4 + i4) + (i4 + i4 )= 2i4 + 2i4 = 2(1) + 2(1) = 2 + 2 = ?

but you can put it this way:

i4 + i4 + i4 + i4 = 4i4 = 4(1) = 4

 

and since

 i4 + i4 + i4 + i4 = i4 + i4 + i4 + i4

then

2 + 2 = 4

*1 is the neutral number of multiplication

note: I just made that one up using the imaginary numbers (i don't know if they are called the same in english) I learnd my math in french and some times the name change but not the numbers ;)

note 2: this is not a real theorem i made that one up

 



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lol NO!

2+2=CHUCK NORRIS

DUHH.... lol



chapset said:

lets use imaginary numbers to resolve this problem

z= ai + b

 where:

i is the imaginary part

we can make b = 0, because 0 is a neutral number

i = √(-1)

i 2 = -1

i4 = 1

i4 + i4 = 2i4 = 2(1)*  = 2

i4 + i4 + i4 + i4 = (i4 + i4) + (i4 + i4 )= 2i4 + 2i4 = 2(1) + 2(1) = 2 + 2 = ?

but you can put it this way:

i4 + i4 + i4 + i4 = 4i4 = 4(1) = 4

 

and since

 i4 + i4 + i4 + i4 = i4 + i4 + i4 + i4

then

2 + 2 = 4

*1 is the neutral number of multiplication

note: I just made that one up using the imaginary numbers (i don't know if they are called the same in english) I learnd my math in french and some times the name change but not the numbers ;)

 

note 2: this is not a real theorem i made that one up

 

yeah called imaginary numbers in England too!

 



Tispower1 said:
chapset said:

lets use imaginary numbers to resolve this problem

z= ai + b

 where:

i is the imaginary part

we can make b = 0, because 0 is a neutral number

i = √(-1)

i 2 = -1

i4 = 1

i4 + i4 = 2i4 = 2(1)*  = 2

i4 + i4 + i4 + i4 = (i4 + i4) + (i4 + i4 )= 2i4 + 2i4 = 2(1) + 2(1) = 2 + 2 = ?

but you can put it this way:

i4 + i4 + i4 + i4 = 4i4 = 4(1) = 4

 

and since

 i4 + i4 + i4 + i4 = i4 + i4 + i4 + i4

then

2 + 2 = 4

*1 is the neutral number of multiplication

 

note: I just made that one up using the imaginary numbers (i don't know if they are called the same in english) I learnd my math in french and some times the name change but not the numbers ;)

 

note 2: this is not a real theorem i made that one up

 

yeah called imaginary numbers in England too!

 

good to know

 



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dtewi said:
No, they used Square Roots. As you should know, an equation usually has as many solutions as its highest degree.

For example, X^2 = 1 has two solutions, -1 and 1. Does this mean -1 and 1 are equal though?

 

I wasn't talking about that problem up there.  I already explained the issue with that one way up above.  You asked this question: "Do you want me to show you two others so you can prove it wrong?"  I was responding to that.  I was guessing they were the other ones where it divides by zero, take the log of a negative number, etc.



The Ghost of RubangB said:
I would use the scientific method, and take 2 dumbasses, and another 2 dumbasses, and then count the total. I would do this ten billion times, and then write a scientific law that 2 + 2 = 4. Then I'd kick you in the nuts.

 

The power of deduction is hardly scientific. If I see 100 white swans, then the 101th swan must be white aswell...

 

All science starts with definitions. How do you define 4 and 2?



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