I already know the answer (In fact, after watching 21 I read the entire Wikipedia article of this problem), so I'll leave it to another person to solve it
I already know the answer (In fact, after watching 21 I read the entire Wikipedia article of this problem), so I'll leave it to another person to solve it
@nordlead : I'm not giving up on your problem. I've been checking this thread from work and answering in my breaks but your problem needs more than the 5-10 minutes I can spare throughout the day.
Signature goes here!
the last one only took me like 2 minutes to solve, but probability is one of my favorite subjects! Granted, the VGC problem is actually very very tough, but it is more than just a puzzle, it is really a small example of the difference between humans and machines, theroms, axims and all sorts of wonderful math topics.
I'd post easier ones, but they seem so obvious to me that I don't feel like it would be a challenge to anyone.
nordlead said: the last one only took me like 2 minutes to solve, but probability is one of my favorite subjects! I'd post easier ones, but they seem so obvious to me that I don't feel like it would be a challenge to anyone. |
Impossible it takes more than 2 minutes to read!! Just kidding.... I'll read it now!
Signature goes here!
I edited my above post
nordlead said: Since no one else seems to be posting these, i'll post another. This one is long, but is very interesting EDIT: Before I give the answer to my previous hard problem, I'm trying to find the actual name of it. I was told it was a famous puzzle, but I can't remember the name of it. |
He should change doors. I'm not sure about the percentages but if he's standing in front of a tiger door, the guards had no choice in which door to open. So since there's a chance that the door they opened was because they had no choice, the prince should choose the other door.
Edit : For the percentages I think it's 66% happy ending if he chooses the other door.
Signature goes here!
By changing doors he gets 2/3 change.
Originally, there was a 1/3 change he was correct.
Thus, that is 1/3 change still.
That means there is a 2/3 change that the other is correct.
Okay, I have a riddle. I'm not very good at putting these though, but I'll give it a shot.
You recieve two boxes with a number inside each box. The two numbers are different but you don't know what they are. You pick one box to open, read the number inside and then guess if the number in the other box is larger or smaller. You win if you guess correctly, and lose otherwise. Is there anyway that you can win the game with more than 50% chances no matter what the two numbers are?
http://www.vgchartz.com/games/userreviewdisp.php?id=261
That is VGChartz LONGEST review. And it's NOT Cute Kitten DS
correct!
Oyvoyvoyv has a good explanation, but if you want a more thorough answer you can go here
http://www.amazeingart.com/fun/lady-tiger-answer.html
EDIT: awesome, I'm in your sig
Oyvoyvoyv said:
You recieve two boxes with a number inside each box. The two numbers are different but you don't know what they are. You pick one box to open, read the number inside and then guess if the number in the other box is larger or smaller. You win if you guess correctly, and lose otherwise. Is there anyway that you can win the game with more than 50% chances no matter what the two numbers are?
|
If the numbers that are in the boxes are totally random (that is, they aren't restricted to, say, the first 10 numbers), then you'll always have more chances of winning by saying that in the other box is a larger number (since every number has more numbers that are larger than it than numbers that are smaller than it).
so long as it is an integer in the range [0,∞) then you would guess larger all the time.
If you have a known range, then it is a piece of cake,
If it is from (-∞, ∞) then I don't have a clue.