lets assume we have the following situation at the end of a time limit for a night:(10 players alive)
| L-5 | L-4 | L-3 | L-2 | L-1 | Lynch | |
| Player Y |
Qwertz |
Uiop |
Paul |
|||
| Player X |
Asdfgh |
Jklö |
Z |
|||
| Player Z | Yxcvbn | Y | X | |||
| Paul | Nomnomnom | |||||
this would be a three way tie (this will also apply when no double lynch is allowed due to mylo/lylo or when a tie with no lynch is existant), this would cause a double lynch. To find out which players will be lynched, there will be a made seperate votals, including only the people that are tied. The votes of the people who are contained on this new list will be discarded. The reduced votals would look like this:
| Vote 1 |
Vote 2 |
Vote 3 |
|
| Player Y |
Qwertz |
Uiop |
Paul |
| Player X |
Asdfgh |
Jklö |
|
| Player Z |
Yxcvbn |
||
This means Player Y and Player X will get lynched. In case there is still a tie, I will use the numbers in the OP to decide on a lynch. The numbers will be set modulo 9, so there will be numbers from 0 to 8. Every number will beat the four number above it, and lose against the 4 numbers below it:
0-1-2-3-4-5-6-7-8-0
so 5 would beat 6, 7, 8, 0 and lose against 1, 2, 3, 4 - 6 would win against 7, 8, 0, 1 and lose against 2, 3, 4, 5 and so on.
In case there is again a tie (eg. Player No. 27 and 36 (both mod 9 = 0) the one with the bigger player number will be lynched (player 36). You got a horrible player number? Tough luck, go complain to someone who cares, or just don't get lynched, because basically, you should be, but multi-lynchs beyond 2 are just bat shit crazy.
In case of player vs. no lynch a tie in the reduced votals will cause a no lynch.
