That is correct.

And I was too slow.

Three logicians sit in a circle, each with hat on their head with a number on it, that others can see but not themselves. They know for a fact that two of the hats add up to third, at least once.
Logician one: I do not know my number
Logician two: I do not know my number
Logician three: I do not know my number.
Logician one: Fifty.

What do the other two hats say?

20 and 30

I'd explain why but it's almost 5am so I'll opt for sleep instead

I'm reaaaaly sorry, but I forgot to say that it is known by the logicians that all numbers are equal or greater than 0, and are whole numbers. Otherwise, the problem is unsolvable.

Here's an easier one: there is a pot of wine and a pot of water, of equal sizes. One takes a spoonfull of the wine and puts it in the water. Then, one puts a spoonfull of the mixture into the wine. Is there more water in the wine or wine in the water?

And this thread is dying already. Oh well, so be it.

20 and 30 is sadly incorrect.

The answer I would get is the same amoutn, but considering that wine is almost entirely made of water, one could say your answer is the better one. I'll make an effort to search for easier enigmas, (considering people don't want to think about them more than a few minutes.) In the meantime, why don't you post one?

No it's not.

If two people have the same number, then the third person immediately knows his number is the sum of those two, because the alternative, that he has the difference of those two, is impossible, since 0 is not positive. For any other combination of numbers, A cannot determine whether his number is the sum or difference of two numbers in the first round.

So, the only ways for B to know what his number is when A did not are when the two numbers B sees are the same, and they are in the ratio 2:1 with the larger number on A. In the latter case, if B has the difference, or the same as C, then A would have known immediately when he saw two identical numbers, so he knows A:B:C are in ratio 2:3:1.

The reasoning continues in this fashion, each turn the logician being able to know what his number is only when the other alternative would have given it away to another logician previously. So when C goes, he knows his hat is neither the same as A's, nor the same as B's, nor half A's. He determines his number if A and B are identical, or if the ratio A:B:C is 1:2:3, 2:1:3, or 2:3:5.

So when A goes again, he knows his number is not equal to or twice either of the others, not half of B's, and not in a 2:3 ratio with B's. He determines his number when A:B:C are in any of these ratios: 3:2:1, 3:1:2, 4:3:1, 4:1:3, 5:2:3, 8:3:5. (In each case, the alternative is a combination somebody else would have already solved.) Out of these, only 5:2:3 allows A's number to be 50.

A sultan passes away and bequeaths his entire fortune to just one of his two sons. However the sultan wished to teach them humility first in order to make them worthy of his position, so he decreed that whomever of his son's camels came last in a race to the nearest town, they would gain everything and the other would get nothing.

The sons spent weeks waiting in their palace, trying to convince the other to win the race, but to no avail. So they decided to speak to the wise man. In his humble tent, the wise man heard their pleas and uttered a short sentence. After which the sons dashed out of the tent, leapt on their camels and sped off to the nearest town as fast as they could.

What did the wise man say?